Project Euler problem 16

Source code available on GitHub.

$$2^{15} = 32768$ and the sum of its digits is $3 + 2 + 7 + 6 + 8 = 26$. What is the sum of the digits of the number $2^{1000}$?$

Easy. Define a quick digits function to return a tuple of the digits of `N`:

def digits(N):
    return tuple(int(i) for i in str(N))

Now just sum the digits of $2^{1000}$ . Done.

def digits(N):
    return tuple(int(i) for i in str(N))

print(sum(digits(2**1000)))